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java.lang.Objectorg.archiviststoolkit.mydomain.LocationsComparator
public class LocationsComparator
| Constructor Summary | |
|---|---|
| LocationsComparator() | |
| Method Summary | |
|---|---|
|  int | compare(java.lang.Object o1,
        java.lang.Object o2)Compares its two arguments for order. | 
| Methods inherited from class java.lang.Object | 
|---|
| clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait | 
| Methods inherited from interface java.util.Comparator | 
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| equals | 
| Constructor Detail | 
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public LocationsComparator()
| Method Detail | 
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public int compare(java.lang.Object o1,
                   java.lang.Object o2)
The implementor must ensure that sgn(compare(x, y)) == -sgn(compare(y, x)) for all x and y. (This implies that compare(x, y) must throw an exception if and only if compare(y, x) throws an exception.)
The implementor must also ensure that the relation is transitive: ((compare(x, y)>0) && (compare(y, z)>0)) implies compare(x, z)>0.
Finally, the implementer must ensure that compare(x, y)==0 implies that sgn(compare(x, z))==sgn(compare(y, z)) for all z.
It is generally the case, but not strictly required that (compare(x, y)==0) == (x.equals(y)). Generally speaking, any comparator that violates this condition should clearly indicate this fact. The recommended language is "Note: this comparator imposes orderings that are inconsistent with equals."
compare in interface java.util.Comparatoro1 - the first object to be compared.o2 - the second object to be compared.
java.lang.ClassCastException - if the arguments' types prevent them from
                            being compared by this Comparator.| 
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